Reply #36: my calcs: [View All]

363 acres x 43,560 SF/acre = 15,812,280 SF/50,000 homes = 316 SF per home, or 138 units/acre.

to retain parks, lets pick a %, say 25% as the amount of existing green space to be retained. that leaves 272.25 acres to develop. the required density goes up to 184 units/acre.

streets are going to take up another 25% of the site, easy. the density is now 275 units/acre.

lets imagine a 25 story apartment building, w/ (10) 500 SF units/floor (small for even a 1 br.) = 6000 SF footprint min. with circulation & elevators, total of 250 units/building. you need 200 of those to get to 50,000. that's 1,200,000 SF. at the minimum. how close are they to each other? is this a desirable living arrangement for families? etc. etc.

overall, i guess your calcs are right, but, man, i wouldn't want to live there.