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bertha katzenengel (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 12:12 PM Original message |
Help with math problem -- and please keep your answer simple . . . |
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unpossibles (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 12:17 PM Response to Original message |
1. the total divided by 13 instead of 20 |
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Beer Snob-50 (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 12:18 PM Response to Original message |
2. I would simply divide the total bill by the 13 |
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KitchenWitch (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 12:46 PM Response to Original message |
3. It depends |
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petronius (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 12:50 PM Response to Original message |
4. Submit the full bill to each one of the 20 clients |
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flvegan (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 12:55 PM Response to Original message |
5. But then aren't you overcharging those 13 clients? |
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Crabby Appleton (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 01:01 PM Response to Reply #5 |
7. I Agree. That would be my answer. |
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suninvited (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 02:01 PM Response to Reply #5 |
10. I agree with this answer |
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Beer Snob-50 (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 02:15 PM Response to Reply #10 |
11. the way the problem reads, |
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OPERATIONMINDCRIME (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 01:00 PM Response to Original message |
6. I Think It's A Clarify Further With Your Boss Problem. |
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JustABozoOnThisBus (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 01:54 PM Response to Original message |
8. Divide by 20 |
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Fredda Weinberg (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 02:17 PM Response to Reply #8 |
12. Literally correct n/t |
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Rabrrrrrr (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 02:01 PM Response to Original message |
9. Divide it by 13 instead of 20. |
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yellowcanine (1000+ posts) Send PM | Profile | Ignore | Mon Feb-11-08 02:20 PM Response to Original message |
13. This is not a math problem. It is an ethics problem. If 7 clients can't be charged, it is |
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DU AdBot (1000+ posts) | Tue Apr 30th 2024, 08:46 AM Response to Original message |
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