Hillary Clinton
Related: About this forumThere are some over at the Sanders group that have a serious math problem.
On more than one occasion they get confused and think that the automatic delegates are not included when determining if a candidate has the needed delegates.
They want to use the majority of all delegates as the winning number needed but it has to come entirely from the pledged delegate group. The convention rules does not exclude automatic delegates nor do they defined it only as pledged delegates.
It is the basis for their argument that there will be a contested convention allowing Sanders to win the nomination.
Gomez163
(2,039 posts)DURHAM D
(32,609 posts)72DejaVu
(1,545 posts)DemonGoddess
(4,640 posts)reading, writing, and arithmetic?
beachbum bob
(10,437 posts)To be expected to deny reality....
Buzz Clik
(38,437 posts)I weary of them.
stopbush
(24,396 posts)the first ballot.
Gomez163
(2,039 posts)johnp3907
(3,731 posts)They must be really good at math because I'm really bad at it and I can't make head nor tail of this:
http://www.democraticunderground.com/1280186766
LiberalFighter
(50,928 posts)He got it wrong on what Sanders would need. But using his math requiring 2,383 delegates from just the pledged delegates. He would need 1,012 of the remaining 1,016 delegates. That is just over 99.6% needed. How out of this universe is that? Maybe because there is a .4% margin they think they have a chance.
IamMab
(1,359 posts)That's a great quote I read somewhere, although the attribution escapes me right now. It's not my quote, I'll admit, but it's still a good one.