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DetlefK

(16,423 posts)
Sat Feb 13, 2016, 01:50 PM Feb 2016

Mathematical question

So, it's possible to expand a function e^x into a series of x^n.

How can I do the reverse?

How could I expand x^n into a series of exponential functions m^x ?

Google always brings me back to a Taylor-expansion of e^x.



Is there some special name for the expansion I'm looking for?
Where should I start looking?

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Mathematical question (Original Post) DetlefK Feb 2016 OP
Interesting question. JonLeibowitz Feb 2016 #1
The problem is that x^n is a polynomial, and m^x is exponential. phantom power Feb 2016 #2

JonLeibowitz

(6,282 posts)
1. Interesting question.
Sat Feb 13, 2016, 02:00 PM
Feb 2016

Are you familiar with Fourier series? Fourier series expand a function very similarly to how you describe:

f(x) = sum(c_n e^(2*pi*i(n/T) x)), with T the period.

Due to the presence of the imaginary unit "i" this represents f in terms of frequencies, so it is not precisely as you ask.

The generalization of this is the Fourier transform which is a representation for non-periodic functions (look up the Gibbs phenomena for how Fourier series fail).

To your direct question, there is a reason you are having a difficult time: there is no compelling reason for such an expansion. A good reason that people talk about Taylor series is that the polynomial representation (powers of x) allows you to obtain estimates for the error you commit when you only use a limited number of terms (the full Taylor series is infinitely long). Exponential functions grow very, very, very, fast so the error estimates would be a nightmare.

This does not apply to the Fourier series I listed above since exponentials of imaginary units can be bounded by 1.

I hope this helps.

phantom power

(25,966 posts)
2. The problem is that x^n is a polynomial, and m^x is exponential.
Tue Feb 16, 2016, 12:03 PM
Feb 2016

So you are trying to sum a family of functions that grow faster than polynomial to equal a polynomial. You might get something that locally converges over a finite interval, but in general I don't think it's going to work very well.

Stepping back, what are you trying to do?

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