Bernie Sanders speaks during a campaign rally at the Century Center on May 1, in South Bend, India

Bernie Sanders speaks during a campaign rally at the Century Center on May 1, in South Bend, Indiana. | Getty


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It's mathematically impossible for Bernie to win with pledged delegates

By Gabriel Debenedetti

05/03/16 11:02 PM EDT

There’s one more reason for Bernie Sanders focus his energy on winning over super delegates — it's now mathematically impossible for him to reach the magic number for the Democratic nomination by winning the remaining pledged delegates alone.

Here's how it works: After winning Indiana, Sanders has 1,399 pledged delegates and superdelegates to his name, according to the Associated Press' count. That means he needs 984 more to reach the threshold of 2,383 needed to win.

The remaining contests, however — Guam, West Virginia, Kentucky, Oregon, Virgin Islands, Puerto Rico, California, Montana, New Jersey, New Mexico, North Dakota, South Dakota, and the District of Columbia — only have 933 pledged delegates to offer.

So even if Sanders were to win 100 percent of the pledged delegates in each of those states, he wouldn't make it past the mark.



....................of the 719 super delegates,
Clinton leads 520 to 39.



Read more: http://www.politico.com/blogs/2016-dem-primary-live-updates-and-results/2016/05/math-says-bernie-sanders-is-finished-222775#ixzz47jj62hcW